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5x^2+0.8x=0.40
We move all terms to the left:
5x^2+0.8x-(0.40)=0
We add all the numbers together, and all the variables
5x^2+0.8x-(0.4)=0
We add all the numbers together, and all the variables
5x^2+0.8x-0.4=0
a = 5; b = 0.8; c = -0.4;
Δ = b2-4ac
Δ = 0.82-4·5·(-0.4)
Δ = 8.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.8)-\sqrt{8.64}}{2*5}=\frac{-0.8-\sqrt{8.64}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.8)+\sqrt{8.64}}{2*5}=\frac{-0.8+\sqrt{8.64}}{10} $
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